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redeclaring an option with the same type is not an error

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This commit is contained in:
Maxime Coste 2013-04-17 19:10:51 +02:00
parent 21f487417b
commit 021756dfd4
1 changed files with 13 additions and 2 deletions
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15
src/option_manager.hh
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@ -27,6 +27,7 @@ public:
template<typename T> const T& get() const;
template<typename T> void set(const T& val);
template<typename T> bool is_of_type() const;
virtual String get_as_string() const = 0;
virtual void set_from_string(const String& str) = 0;
@ -139,6 +140,11 @@ template<typename T> void Option::set(const T& val)
return typed_opt->set(val);
}
template<typename T> bool Option::is_of_type() const
{
return dynamic_cast<const TypedOption<T>*>(this) != nullptr;
}
template<typename T>
auto find_option(T& container, const String& name) -> decltype(container.begin())
{
@ -155,8 +161,13 @@ public:
template<typename T>
Option& declare_option(const String& name, const T& value)
{
if (find_option(m_options, name) != m_options.end())
throw runtime_error("option " + name + " already declared");
auto it = find_option(m_options, name);
if (it != m_options.end())
{
if ((*it)->is_of_type<T>())
return **it;
throw runtime_error("option " + name + " already declared with different type");
}
m_options.emplace_back(new TypedOption<T>{*this, name, value});
return *m_options.back();
}